f(x)x^3=2x^2-3x+20

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Solution for f(x)x^3=2x^2-3x+20 equation: 


Simplifying
f(x) * x3 = 2x2 + -3x + 20

Multiply f * x
fx * x3 = 2x2 + -3x + 20

Multiply fx * x3
fx4 = 2x2 + -3x + 20

Reorder the terms:
fx4 = 20 + -3x + 2x2

Solving
fx4 = 20 + -3x + 2x2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by 'x4'.
f = 20x-4 + -3x-3 + 2x-2

Simplifying
f = 20x-4 + -3x-3 + 2x-2

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